/Subtype /Form /ProcSet[/PDF] 1.014 0 0 1.007 531.485 253.697 cm 0 g /Meta87 Do q 0.564 G 1.007 0 0 1.007 67.753 737.003 cm 0 w /Length 99 /ProcSet[/PDF/Text] >> /Meta1198 1216 0 R /Meta547 563 0 R /ProcSet[/PDF/Text] >> 1.007 0 0 1.007 67.753 356.08 cm /Length 59 0 G Q /Type /XObject (x) Tj /Font << 1230 0 obj stream >> /ProcSet[/PDF/Text] BT q /Meta1638 1658 0 R Q q /Matrix [1 0 0 1 0 0] >> /F3 17 0 R BT endobj 1.007 0 0 1.007 271.012 779.16 cm /BBox [0 0 534.67 16.44] q Q q q /Meta780 796 0 R 1.502 5.203 TD /Meta1388 Do /ProcSet[/PDF/Text] /Type /XObject Q 679.036 146.798 m Q 1.005 0 0 1.007 102.382 200.248 cm q q Q /Type /XObject endobj /Font << /BBox [0 0 23.896 16.44] /F3 12.131 Tf /Meta973 989 0 R /Font << q /FontDescriptor 10 0 R 0 g 1708 0 obj 1647 0 obj 0 G q 923 0 obj Q /Meta649 Do 0 g /Font << endobj 0 g >> 811 0 obj /Matrix [1 0 0 1 0 0] >> /Font << Q 1048 0 obj >> 1.005 0 0 1.007 79.798 548.047 cm /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] q 1.007 0 0 1.007 551.058 651.182 cm 6.746 5.203 TD >> /Meta1270 Do 0 g -0.316 Tw 0.68 Tc BT /F3 12.131 Tf stream 1677 0 obj /Subtype /Form /Matrix [1 0 0 1 0 0] /Resources<< stream q Q /ProcSet[/PDF/Text] endstream >> q 1 i q Q endobj (A\)) Tj 198 0 obj 1 g /Length 54 q /Meta534 Do /F3 12.131 Tf Q 1.007 0 0 1.007 271.012 372.642 cm q /Type /XObject /Resources<< /FormType 1 1.014 0 0 1.007 111.416 773.891 cm q >> endstream /FormType 1 endobj 0 g /F3 12.131 Tf /Type /XObject /ProcSet[/PDF/Text] ET /Length 59 S Q 1 i /FormType 1 967 0 obj /I0 Do /Font << 0.51 Tc >> endstream q >> stream endstream 1 i 0.68 Tc q >> /FormType 1 endstream Q /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] endobj 0 5.203 TD q >> endstream /BBox [0 0 88.214 16.44] /F4 12.131 Tf /Meta283 297 0 R 0 g endstream /Subtype /Form q /Matrix [1 0 0 1 0 0] 1 i 0.737 w /Subtype /Form 0.369 Tc endstream (=) Tj 1293 0 obj /BBox [0 0 15.59 16.44] 0.458 0 0 RG /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] 408 0 obj 0.564 G q /Meta429 Do >> /BBox [0 0 30.642 16.44] /Type /XObject q 607 0 obj Q << 0 g /ProcSet[/PDF] 1 i /Matrix [1 0 0 1 0 0] /Type /XObject /FormType 1 Q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /Font << /ProcSet[/PDF/Text] Q 0 g 1.007 0 0 1.007 551.058 350.81 cm /FormType 1 /Meta671 687 0 R /FormType 1 q /ProcSet[/PDF/Text] >> Q Q [(1)-25(0\))] TJ 0.458 0 0 RG Q endobj 0 g 1 g q ET stream q q Q 1.007 0 0 1.007 551.058 706.138 cm /F4 24 0 R q Q >> 1 g /Subtype /Form endobj /ProcSet[/PDF/Text] 0 G 1.005 0 0 1.007 102.382 474.271 cm /Meta1384 Do q >> q q 1.005 0 0 1.007 102.382 683.553 cm /Resources<< 1.005 0 0 1.007 79.798 829.599 cm endstream /BBox [0 0 534.67 16.44] >> Q >> 1 g /ProcSet[/PDF] q 0 5.336 TD 1047 0 obj /F3 12.131 Tf Q 0 g /Matrix [1 0 0 1 0 0] /Meta1485 Do /ProcSet[/PDF/Text] /Resources<< stream Q >> /Length 78 >> >> >> 0 G BT /FormType 1 /BBox [0 0 15.59 16.44] /BBox [0 0 88.214 16.44] endobj /Subtype /Form endobj 18 0 obj endobj /ProcSet[/PDF/Text] 0.737 w 0 g Q Q endstream /Length 12 1562 0 obj >> 1 i Q /BBox [0 0 534.67 20.154] endstream endobj 1 i 1646 0 obj /Length 59 /Type /XObject endobj << endstream /Length 69 0 w 722.699 843.902 l endobj /ProcSet[/PDF] endstream 0 G /F3 12.131 Tf 13.464 5.203 TD 1 i /Resources<< 1061 0 obj q << /ProcSet[/PDF] stream q q 0 G q >> /Type /XObject /Length 118 stream /Meta974 990 0 R endobj /Matrix [1 0 0 1 0 0] 0 G Graph y = 1x + 4 x y 7 using the table method: 11. 0 w << BT BT ( x ) Tj /MaxWidth 2000 >> /Meta1428 1446 0 R /Font << BT >> ET [(1)-25(3\))] TJ Q Q Q Use the graph to determine the age at which both companies charge the same premium. /Meta794 810 0 R /Meta1695 1715 0 R /Type /XObject q /Meta1015 Do /Matrix [1 0 0 1 0 0] q /ProcSet[/PDF] /Type /XObject 1 i q /Resources<< 0 w stream << /Matrix [1 0 0 1 0 0] q >> /Type /XObject q q /FormType 1 q /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 45.168 746.789 cm /F4 12.131 Tf endobj /Length 16 q /Matrix [1 0 0 1 0 0] Q Q Q /ProcSet[/PDF/Text] ET /Resources<< 1.007 0 0 1.007 130.989 572.137 cm (620) Tj stream >> << Q endstream endstream 0 5.203 TD q 1 i /Subtype /Form 1 g /StemH 94 1.007 0 0 1.007 551.058 572.137 cm Q q /Font << q q /Resources<< Q q 0 20.154 m /Resources<< 1.007 0 0 1.007 271.012 432.867 cm /Meta762 778 0 R (6) Tj /Meta979 Do >> /ProcSet[/PDF] /Type /XObject Q 1.014 0 0 1.007 111.416 704.632 cm endobj 1 g /BBox [0 0 15.59 16.44] /Subtype /Form /Meta1468 Do >> Q << /F4 12.131 Tf q q 154 0 obj >> /ProcSet[/PDF] /Type /XObject 1 i /F3 12.131 Tf 0 g Q 1105 0 obj /Meta1477 1495 0 R /Type /XObject /Resources<< /Length 73 Q /BBox [0 0 88.214 16.44] 0 g endstream stream Q /Subtype /Form endobj >> /Length 54 /Subtype /Form 1 g endobj 1 i 0.786 Tc 1 i /BBox [0 0 88.214 16.44] /Subtype /Form 0.281 Tc 0 g /Matrix [1 0 0 1 0 0] /Type /XObject endobj Q /Meta533 Do Q endstream /ProcSet[/PDF] << 0 w /Meta448 462 0 R /Length 167 /Resources<< q << 1.014 0 0 1.007 531.485 404.26 cm >> 0 g /F3 17 0 R /Subtype /Form /F4 12.131 Tf /F3 12.131 Tf 1 i /Resources<< /F3 12.131 Tf Q q 0 5.336 TD BT Q ET 0 w /Matrix [1 0 0 1 0 0] q Q >> ET /F3 12.131 Tf ET Q q >> Q 1 i ET Q 1.005 0 0 1.007 102.382 146.798 cm 0 g /F3 17 0 R /BBox [0 0 17.177 16.44] << (7) Tj Q 0.564 G >> - eliminate one variable from both equations STEP #1: Put both equations in SAME FORM (Ax + By = C) STEP #2: SELECT A VARIABLE to eliminate (x or y) STEP #3: As needed, make that variable in both equations have same coefficient values (ex: -3x and 3x OR 2x and 2x) by MULTIPLICATION to each equation. /Meta1022 Do /Length 69 0.458 0 0 RG 0 g q /Length 63 0 G /Matrix [1 0 0 1 0 0] /Subtype /Form /Meta1129 Do >> /FormType 1 1 i Q 0.737 w /Resources<< 1 i stream /Type /XObject Q 0 g q 1 i /Subtype /Form /Subtype /Form /ProcSet[/PDF/Text] << /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] /Type /XObject (31) Tj >> /Type /XObject /Matrix [1 0 0 1 0 0] /F4 24 0 R 1.007 0 0 1.006 130.989 359.844 cm (=) Tj 0 G Q /Type /XObject BT /Length 12 Q /Font << 1 i 1 i >> Q Q Q Q /BBox [0 0 15.59 16.44] 0 g /Subtype /Form q >> (3) 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